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SELECT count(*) FROM head WHERE age > 56
CREATE TABLE head (age INTEGER)
部门中有多少人年龄大于56岁?
SELECT name , born_state , age FROM head ORDER BY age
CREATE TABLE head (born_state VARCHAR, name VARCHAR, age VARCHAR)
列出按年龄排序的部门负责人的姓名、出生地和年龄。
SELECT creation , name , budget_in_billions FROM department
CREATE TABLE department (budget_in_billions VARCHAR, name VARCHAR, creation VARCHAR)
列出每个部门的创建年份、名称和预算。
SELECT max(budget_in_billions) , min(budget_in_billions) FROM department
CREATE TABLE department (budget_in_billions INTEGER)
部门的最高预算和最低预算是多少?
SELECT avg(num_employees) FROM department WHERE ranking BETWEEN 10 AND 15
CREATE TABLE department (num_employees INTEGER, ranking INTEGER)
排名在10到15之间的部门的平均雇员人数是多少?
SELECT name FROM head WHERE born_state != '浙江'
CREATE TABLE head (born_state VARCHAR, name VARCHAR)
出生在“浙江”州以外的人的名字是什么?
SELECT DISTINCT T1.creation FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T3.born_state = '河南'
CREATE TABLE department (creation VARCHAR, department_id VARCHAR), CREATE TABLE management (head_id VARCHAR, department_id VARCHAR), CREATE TABLE head (born_state VARCHAR, head_id VARCHAR)
出生于“河南”州的秘书所管理的各部门的不同创建年份是什么?
SELECT born_state FROM head GROUP BY born_state HAVING count(*) >= 3
CREATE TABLE head (born_state VARCHAR)
至少有3个负责人出生的州的名字是什么?
SELECT creation FROM department GROUP BY creation ORDER BY count(*) DESC LIMIT 1
CREATE TABLE department (creation VARCHAR)
大多数部门在哪一年成立?
SELECT T1.name , T1.num_employees FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id WHERE T2.temporary_acting = '是'
CREATE TABLE department (num_employees VARCHAR, name VARCHAR, department_id VARCHAR), CREATE TABLE management (temporary_acting VARCHAR, department_id VARCHAR)
显示由临时代理值为“是”的负责人所管理的部门的员工姓名和数目?
SELECT count(DISTINCT temporary_acting) FROM management
CREATE TABLE management (temporary_acting VARCHAR)
有多少个代理状态?
SELECT count(*) FROM department WHERE department_id NOT IN (SELECT department_id FROM management);
CREATE TABLE department (department_id VARCHAR), CREATE TABLE management (department_id VARCHAR)
有多少部门由没有提到的负责人领导?
SELECT DISTINCT T1.age FROM management AS T2 JOIN head AS T1 ON T1.head_id = T2.head_id WHERE T2.temporary_acting = '是'
CREATE TABLE management (head_id VARCHAR, temporary_acting VARCHAR), CREATE TABLE head (head_id VARCHAR, age VARCHAR)
那些正在代理的负责人有哪些不同的年龄?
SELECT T3.born_state FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T1.name = '财政部' INTERSECT SELECT T3.born_state FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T1.name = '国土安全部'
CREATE TABLE department (name VARCHAR, department_id VARCHAR), CREATE TABLE management (head_id VARCHAR, department_id VARCHAR), CREATE TABLE head (born_state VARCHAR, head_id VARCHAR)
列出“财政部”部门秘书和“国土安全部”秘书出生的州。
SELECT T1.department_id , T1.name , count(*) FROM management AS T2 JOIN department AS T1 ON T1.department_id = T2.department_id GROUP BY T1.department_id HAVING count(*) > 1
CREATE TABLE management (department_id VARCHAR), CREATE TABLE department (name VARCHAR, department_id VARCHAR)
哪个部门有不止一个负责人?列出ID、姓名和人数。
SELECT head_id , name FROM head WHERE name LIKE '强'
CREATE TABLE head (head_id VARCHAR, name VARCHAR)
哪个负责人的名字有“强”这个子串?列出ID和姓名。
SELECT count(*) FROM farm
CREATE TABLE farm (Id VARCHAR)
那里有多少个农场?
SELECT count(*) FROM farm
CREATE TABLE farm (Id VARCHAR)
计算农场的数量。
SELECT Total_Horses FROM farm ORDER BY Total_Horses ASC
CREATE TABLE farm (Total_Horses VARCHAR)
按升序列出农场里的马的总数。
SELECT Total_Horses FROM farm ORDER BY Total_Horses ASC
CREATE TABLE farm (Total_Horses VARCHAR)
按照升序排列,每一个农场的马的总数是什么?
SELECT Hosts FROM farm_competition WHERE Theme != '外星人'
CREATE TABLE farm_competition (Theme VARCHAR, Hosts VARCHAR)
什么主持人所主持比赛的主题不是“外星人”?
SELECT Hosts FROM farm_competition WHERE Theme != '外星人'
CREATE TABLE farm_competition (Theme VARCHAR, Hosts VARCHAR)
返回主题不是“外星人”的竞赛的主持人?
SELECT Theme FROM farm_competition ORDER BY YEAR ASC
CREATE TABLE farm_competition (YEAR VARCHAR, Theme VARCHAR)
按年份排序的农场比赛的主题是什么?
SELECT Theme FROM farm_competition ORDER BY YEAR ASC
CREATE TABLE farm_competition (YEAR VARCHAR, Theme VARCHAR)
返回农场比赛的主题,按年份排序。
SELECT avg(Working_Horses) FROM farm WHERE Total_Horses > 5000
CREATE TABLE farm (Total_Horses INTEGER, Working_Horses INTEGER)
拥有超过5000匹马的农场中,平均的工作马的数量是多少?
SELECT avg(Working_Horses) FROM farm WHERE Total_Horses > 5000
CREATE TABLE farm (Total_Horses INTEGER, Working_Horses INTEGER)
给出有5000多匹马的农场的平均工作马的数量。
SELECT max(Cows) , min(Cows) FROM farm
CREATE TABLE farm (Cows INTEGER)
所有农场中,奶牛的最大和最小数量是多少?
SELECT max(Cows) , min(Cows) FROM farm
CREATE TABLE farm (Cows INTEGER)
返回所有农场奶牛的最大和最小数量。
SELECT count(DISTINCT Status) FROM city
CREATE TABLE city (Status VARCHAR)
城市有多少种不同的地位?
SELECT count(DISTINCT Status) FROM city
CREATE TABLE city (Status VARCHAR)
统计不同地位的数量。
SELECT Official_Name FROM city ORDER BY Population DESC
CREATE TABLE city (Official_Name VARCHAR, Population VARCHAR)
按人口降序列出城市的官方名称。
SELECT Official_Name FROM city ORDER BY Population DESC
CREATE TABLE city (Official_Name VARCHAR, Population VARCHAR)
按人口降序排列的城市的官方名称是什么?
SELECT Official_Name , Status FROM city ORDER BY Population DESC LIMIT 1
CREATE TABLE city (Official_Name VARCHAR, Status VARCHAR, Population VARCHAR)
列出人口最多的城市的官方名称和状态。
SELECT Official_Name , Status FROM city ORDER BY Population DESC LIMIT 1
CREATE TABLE city (Official_Name VARCHAR, Status VARCHAR, Population VARCHAR)
居住人数最多的城市的官方名称和状态是什么?
SELECT T2.Year , T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID
CREATE TABLE city (Official_Name VARCHAR, City_ID VARCHAR), CREATE TABLE farm_competition (Host_city_ID VARCHAR, Year VARCHAR)
展示主办比赛城市的年份和正式名称。
SELECT T2.Year , T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID
CREATE TABLE city (Official_Name VARCHAR, City_ID VARCHAR), CREATE TABLE farm_competition (Host_city_ID VARCHAR, Year VARCHAR)
给出每个竞赛的城市的年份和官方名称。
SELECT T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID HAVING COUNT(*) > 1
CREATE TABLE city (Official_Name VARCHAR, City_ID VARCHAR), CREATE TABLE farm_competition (Host_city_ID VARCHAR)
展示举办了不止一次比赛的城市的官方名称。
SELECT T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID HAVING COUNT(*) > 1
CREATE TABLE city (Official_Name VARCHAR, City_ID VARCHAR), CREATE TABLE farm_competition (Host_city_ID VARCHAR)
举办了不止一次比赛的城市的官方名称是什么?
SELECT T1.Status FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE city (Status VARCHAR, City_ID VARCHAR), CREATE TABLE farm_competition (Host_city_ID VARCHAR)
展示主办城市数量最多的城市的状态。
SELECT T1.Status FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE city (Status VARCHAR, City_ID VARCHAR), CREATE TABLE farm_competition (Host_city_ID VARCHAR)
主办过最多比赛的城市的状态如何?
SELECT T2.Theme FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID WHERE T1.Population > 1000
CREATE TABLE city (Population INTEGER, City_ID VARCHAR), CREATE TABLE farm_competition (Host_city_ID VARCHAR, Theme VARCHAR)
请显示拥有超过1000人的主办城市的比赛主题。
SELECT T2.Theme FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID WHERE T1.Population > 1000
CREATE TABLE city (Population INTEGER, City_ID VARCHAR), CREATE TABLE farm_competition (Host_city_ID VARCHAR, Theme VARCHAR)
有超过1000居民的主办城市的比赛主题是什么?
SELECT Status , avg(Population) FROM city GROUP BY Status
CREATE TABLE city (Population INTEGER, Status VARCHAR)
请显示不同城市的地位和各个地位的城市平均人口。
SELECT Status , avg(Population) FROM city GROUP BY Status
CREATE TABLE city (Population INTEGER, Status VARCHAR)
每个城市的状态和平均人口是多少?
SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) ASC
CREATE TABLE city (Status VARCHAR)
请按每个状态的城市的数量排列,显示不同的状态。
SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) ASC
CREATE TABLE city (Status VARCHAR)
返回城市的不同状态,按频率递增排序。
SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE city (Status VARCHAR)
列出城市中最常见的一种状态。
SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE city (Status VARCHAR)
在所有城市中最常见的状态是什么?
SELECT Official_Name FROM city WHERE City_ID NOT IN (SELECT Host_city_ID FROM farm_competition)
CREATE TABLE city (Host_city_ID VARCHAR, Official_Name VARCHAR, City_ID VARCHAR), CREATE TABLE farm_competition (Host_city_ID VARCHAR, Official_Name VARCHAR, City_ID VARCHAR)
列出没有比赛的城市的官方名称。
SELECT Official_Name FROM city WHERE City_ID NOT IN (SELECT Host_city_ID FROM farm_competition)
CREATE TABLE city (Host_city_ID VARCHAR, Official_Name VARCHAR, City_ID VARCHAR), CREATE TABLE farm_competition (Host_city_ID VARCHAR, Official_Name VARCHAR, City_ID VARCHAR)
没有举办过农场比赛的城市的官方名称是什么?
SELECT Status FROM city WHERE Population > 1500 INTERSECT SELECT Status FROM city WHERE Population < 500
CREATE TABLE city (Population INTEGER, Status VARCHAR)
显示人口大于1500和小于500的城市的状态。
SELECT Status FROM city WHERE Population > 1500 INTERSECT SELECT Status FROM city WHERE Population < 500
CREATE TABLE city (Population INTEGER, Status VARCHAR)
人口超过1500的城市和人口低于500的城市,其状态分别是什么?
SELECT Official_Name FROM city WHERE Population > 1500 OR Population < 500
CREATE TABLE city (Population INTEGER, Official_Name VARCHAR)
查找人口大于1500或小于500的城市的官方名称。
SELECT Official_Name FROM city WHERE Population > 1500 OR Population < 500
CREATE TABLE city (Population INTEGER, Official_Name VARCHAR)
人口超过1500或少于500的城市的官方名称是什么?
SELECT Census_Ranking FROM city WHERE Status != "乡村"
CREATE TABLE city (Status VARCHAR, Census_Ranking VARCHAR)
显示不属于“乡村”的城市的人口普查排名。
SELECT Census_Ranking FROM city WHERE Status != "乡村"
CREATE TABLE city (Status VARCHAR, Census_Ranking VARCHAR)
没有“乡村”状态的城市的人口普查排名是多少?
SELECT T1.course_name FROM courses AS T1 JOIN student_course_registrations AS T2 ON T1.course_id = T2.course_Id GROUP BY T1.course_id ORDER BY count(*) DESC LIMIT 1
CREATE TABLE courses (course_name VARCHAR, course_id VARCHAR), CREATE TABLE student_course_registrations (course_Id VARCHAR)
注册学生最多的是哪门课程?
SELECT T1.course_name FROM courses AS T1 JOIN student_course_registrations AS T2 ON T1.course_id = T2.course_Id GROUP BY T1.course_id ORDER BY count(*) DESC LIMIT 1
CREATE TABLE courses (course_name VARCHAR, course_id VARCHAR), CREATE TABLE student_course_registrations (course_Id VARCHAR)
最多注册学生的课程名称是什么?
SELECT student_id FROM student_course_registrations GROUP BY student_id ORDER BY count(*) LIMIT 1
CREATE TABLE student_course_registrations (student_id VARCHAR)
注册一些课程但注册课程最少的学生的ID是什么?
SELECT student_id FROM student_course_registrations GROUP BY student_id ORDER BY count(*) LIMIT 1
CREATE TABLE student_course_registrations (student_id VARCHAR)
注册课程数量最少但是注册了一些课程的学生的ID是什么?
SELECT T2.first_name , T2.last_name FROM candidates AS T1 JOIN people AS T2 ON T1.candidate_id = T2.person_id
CREATE TABLE candidates (candidate_id VARCHAR), CREATE TABLE people (last_name VARCHAR, person_id VARCHAR, first_name VARCHAR)
所有候选人的名字和姓氏是什么?
SELECT T2.first_name , T2.last_name FROM candidates AS T1 JOIN people AS T2 ON T1.candidate_id = T2.person_id
CREATE TABLE candidates (candidate_id VARCHAR), CREATE TABLE people (last_name VARCHAR, person_id VARCHAR, first_name VARCHAR)
所有候选人的名字和姓氏是什么?
SELECT student_id FROM students WHERE student_id NOT IN (SELECT student_id FROM student_course_attendance)
CREATE TABLE students (student_id VARCHAR), CREATE TABLE student_course_attendance (student_id VARCHAR)
列出从不上课的学生的ID?
SELECT student_id FROM students WHERE student_id NOT IN (SELECT student_id FROM student_course_attendance)
CREATE TABLE students (student_id VARCHAR), CREATE TABLE student_course_attendance (student_id VARCHAR)
每一个从未上过课的学生的ID是什么?
SELECT student_id FROM student_course_attendance
CREATE TABLE student_course_attendance (student_id VARCHAR)
列出参加过一些课程的学生的ID?
SELECT student_id FROM student_course_attendance
CREATE TABLE student_course_attendance (student_id VARCHAR)
所有参加过至少一门课程的学生的ID是什么?
SELECT T1.student_id , T2.course_name FROM student_course_registrations AS T1 JOIN courses AS T2 ON T1.course_id = T2.course_id
CREATE TABLE student_course_registrations (student_id VARCHAR, course_id VARCHAR), CREATE TABLE courses (course_name VARCHAR, course_id VARCHAR)
所有上课学生ID是什么?这些课程的名称是什么?
SELECT T2.student_details FROM student_course_registrations AS T1 JOIN students AS T2 ON T1.student_id = T2.student_id ORDER BY T1.registration_date DESC LIMIT 1
CREATE TABLE student_course_registrations (student_id VARCHAR, registration_date VARCHAR), CREATE TABLE students (student_id VARCHAR, student_details VARCHAR)
最近注册课程的学生的具体信息是什么?
SELECT T2.student_details FROM student_course_registrations AS T1 JOIN students AS T2 ON T1.student_id = T2.student_id ORDER BY T1.registration_date DESC LIMIT 1
CREATE TABLE student_course_registrations (student_id VARCHAR, registration_date VARCHAR), CREATE TABLE students (student_id VARCHAR, student_details VARCHAR)
关于最近注册课程的学生,我们有哪些信息?
SELECT count(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T1.course_name = "英语"
CREATE TABLE courses (course_name VARCHAR, course_id VARCHAR), CREATE TABLE student_course_attendance (course_id VARCHAR)
有多少学生参加英语课程?
SELECT count(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T1.course_name = "英语"
CREATE TABLE courses (course_name VARCHAR, course_id VARCHAR), CREATE TABLE student_course_attendance (course_id VARCHAR)
参加英语课程的有多少学生?
SELECT count(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T2.student_id = 171
CREATE TABLE courses (course_id VARCHAR), CREATE TABLE student_course_attendance (student_id VARCHAR, course_id VARCHAR)
ID为171的学生参加了多少门课程?
SELECT count(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T2.student_id = 171
CREATE TABLE courses (course_id VARCHAR), CREATE TABLE student_course_attendance (student_id VARCHAR, course_id VARCHAR)
ID 171的学生实际参加了多少门课程?
SELECT T2.candidate_id FROM people AS T1 JOIN candidates AS T2 ON T1.person_id = T2.candidate_id WHERE T1.email_address = "[email protected]"
CREATE TABLE people (person_id VARCHAR, email_address VARCHAR), CREATE TABLE candidates (candidate_id VARCHAR)
找到电子邮箱为“[email protected]”的候选人的ID。
SELECT T2.candidate_id FROM people AS T1 JOIN candidates AS T2 ON T1.person_id = T2.candidate_id WHERE T1.email_address = "[email protected]"
CREATE TABLE people (person_id VARCHAR, email_address VARCHAR), CREATE TABLE candidates (candidate_id VARCHAR)
候选人的ID是什么,他的电子邮件是“[email protected]”?
SELECT candidate_id FROM candidate_assessments ORDER BY assessment_date DESC LIMIT 1
CREATE TABLE candidate_assessments (assessment_date VARCHAR, candidate_id VARCHAR)
找到最近访问课程的候选人的ID?
SELECT candidate_id FROM candidate_assessments ORDER BY assessment_date DESC LIMIT 1
CREATE TABLE candidate_assessments (assessment_date VARCHAR, candidate_id VARCHAR)
最近访问课程的候选人的ID是什么?
SELECT T1.student_details FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY count(*) DESC LIMIT 1
CREATE TABLE students (student_id VARCHAR, student_details VARCHAR), CREATE TABLE student_course_registrations (student_id VARCHAR)
注册最多课程的学生的具体信息是什么?
SELECT T1.student_details FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY count(*) DESC LIMIT 1
CREATE TABLE students (student_id VARCHAR, student_details VARCHAR), CREATE TABLE student_course_registrations (student_id VARCHAR)
注册课程最多的学生的详细情况是什么?
SELECT T1.student_id , count(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id
CREATE TABLE students (student_id VARCHAR), CREATE TABLE student_course_registrations (student_id VARCHAR)
列出注册一些课程的学生的ID和注册课程的数量?
SELECT T1.student_id , count(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id
CREATE TABLE students (student_id VARCHAR), CREATE TABLE student_course_registrations (student_id VARCHAR)
对于每个注册了某些课程的学生,他们注册了多少课程?
SELECT T3.course_name , count(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id JOIN courses AS T3 ON T2.course_id = T3.course_id GROUP BY T2.course_id
CREATE TABLE students (student_id VARCHAR), CREATE TABLE student_course_registrations (student_id VARCHAR, course_id VARCHAR), CREATE TABLE courses (course_name VARCHAR, course_id VARCHAR)
每门课程有多少注册学生?列出课程名称和注册的学生人数?
SELECT T3.course_name , count(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id JOIN courses AS T3 ON T2.course_id = T3.course_id GROUP BY T2.course_id
CREATE TABLE students (student_id VARCHAR), CREATE TABLE student_course_registrations (student_id VARCHAR, course_id VARCHAR), CREATE TABLE courses (course_name VARCHAR, course_id VARCHAR)
对于每个课程ID,注册了多少学生,课程名称是什么?
SELECT candidate_id FROM candidate_assessments WHERE asessment_outcome_code = "通过"
CREATE TABLE candidate_assessments (asessment_outcome_code VARCHAR, candidate_id VARCHAR)
找到评估码为“通过”的候选人ID?
SELECT candidate_id FROM candidate_assessments WHERE asessment_outcome_code = "通过"
CREATE TABLE candidate_assessments (asessment_outcome_code VARCHAR, candidate_id VARCHAR)
成绩代码为及格的候选人的ID是什么?
SELECT T3.cell_mobile_number FROM candidates AS T1 JOIN candidate_assessments AS T2 ON T1.candidate_id = T2.candidate_id JOIN people AS T3 ON T1.candidate_id = T3.person_id WHERE T2.asessment_outcome_code = "失败"
CREATE TABLE candidates (candidate_id VARCHAR), CREATE TABLE candidate_assessments (asessment_outcome_code VARCHAR, candidate_id VARCHAR), CREATE TABLE people (person_id VARCHAR, cell_mobile_number VARCHAR)
查找评估代码是“失败”的考生的手机号码?
SELECT T3.cell_mobile_number FROM candidates AS T1 JOIN candidate_assessments AS T2 ON T1.candidate_id = T2.candidate_id JOIN people AS T3 ON T1.candidate_id = T3.person_id WHERE T2.asessment_outcome_code = "失败"
CREATE TABLE candidates (candidate_id VARCHAR), CREATE TABLE candidate_assessments (asessment_outcome_code VARCHAR, candidate_id VARCHAR), CREATE TABLE people (person_id VARCHAR, cell_mobile_number VARCHAR)
收到“失败”评估码的候选人的手机号码是多少?
SELECT student_id FROM student_course_attendance WHERE course_id = 301
CREATE TABLE student_course_attendance (student_id VARCHAR, course_id VARCHAR)
那些注册301课程的学生的ID是什么?
SELECT student_id FROM student_course_attendance WHERE course_id = 301
CREATE TABLE student_course_attendance (student_id VARCHAR, course_id VARCHAR)
注册301课程的学生的ID是什么?
SELECT student_id FROM student_course_attendance WHERE course_id = 301 ORDER BY date_of_attendance DESC LIMIT 1
CREATE TABLE student_course_attendance (student_id VARCHAR, course_id VARCHAR, date_of_attendance VARCHAR)
最近注册301课程的学生的ID是什么?
SELECT student_id FROM student_course_attendance WHERE course_id = 301 ORDER BY date_of_attendance DESC LIMIT 1
CREATE TABLE student_course_attendance (student_id VARCHAR, course_id VARCHAR, date_of_attendance VARCHAR)
对于最近注册301课程的学生,他们的ID是什么?
SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id
CREATE TABLE addresses (address_id VARCHAR, city VARCHAR), CREATE TABLE people_addresses (address_id VARCHAR)
找到人的地址的不同城市?
SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id
CREATE TABLE addresses (address_id VARCHAR, city VARCHAR), CREATE TABLE people_addresses (address_id VARCHAR)
人们居住的不同城市有哪些?
SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id JOIN students AS T3 ON T2.person_id = T3.student_id
CREATE TABLE addresses (address_id VARCHAR, city VARCHAR), CREATE TABLE people_addresses (person_id VARCHAR, address_id VARCHAR), CREATE TABLE students (student_id VARCHAR)
找出学生地址的不同城市?
SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id JOIN students AS T3 ON T2.person_id = T3.student_id
CREATE TABLE addresses (address_id VARCHAR, city VARCHAR), CREATE TABLE people_addresses (person_id VARCHAR, address_id VARCHAR), CREATE TABLE students (student_id VARCHAR)
学生居住的不同城市有哪些?
SELECT course_name FROM courses ORDER BY course_name
CREATE TABLE courses (course_name VARCHAR)
按字母顺序列出课程名称?
SELECT course_name FROM courses ORDER BY course_name
CREATE TABLE courses (course_name VARCHAR)
按字母顺序排列的课程名称是什么?
SELECT first_name FROM people ORDER BY first_name
CREATE TABLE people (first_name VARCHAR)
按字母顺序列出人的名字?
SELECT first_name FROM people ORDER BY first_name
CREATE TABLE people (first_name VARCHAR)
按字母顺序排列的人的名字是什么?
SELECT student_id FROM student_course_registrations UNION SELECT student_id FROM student_course_attendance
CREATE TABLE student_course_registrations (student_id VARCHAR), CREATE TABLE student_course_attendance (student_id VARCHAR)
注册课程或参加课程的学生的ID是什么?