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CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Provide the full names and emails of customers whose payments were greater than 70% of the average.

SELECT DISTINCT T2.first_name, T2.last_name, T2.email FROM payment AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id INNER JOIN address AS T3 ON T2.address_id = T3.address_id WHERE T1.amount > ( SELECT AVG(amount) FROM payment ) * 0.7

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

How many films have a rental rate of 0.99?

SELECT COUNT(film_id) FROM film WHERE rental_rate = 0.99

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Among the customers with customer ID of 100 and below, how many of them have Thomas as their last name?

SELECT COUNT(customer_id) FROM customer WHERE last_name = 'Thomas' AND customer_id < 100

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

List the actor's last name that starred the film with the description of "A Thoughtful Drama of a Composer And a Feminist who must Meet a Secret Agent in The Canadian Rockies".

SELECT T1.last_name FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.description = 'A Thoughtful Drama of a Composer And a Feminist who must Meet a Secret Agent in The Canadian Rockies'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Give the title of the film starred by Liza Bergman with the highest replacement cost.

SELECT T3.title FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'Liza' AND T1.last_name = 'Bergman' ORDER BY replacement_cost DESC LIMIT 1

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Among films with store ID of 2, list the title of films with the highest rental rate.

SELECT T1.title FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id WHERE T2.store_id = 2 ORDER BY rental_rate DESC LIMIT 1

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Among the films starred by Angelina Astaire, what is the title of the film with a replacement cost of 27.99?

SELECT T3.title FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'Angelina' AND T1.last_name = 'Astaire' AND T3.replacement_cost = 27.99

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

List the inventory ID of the film titled "African Egg".

SELECT T2.inventory_id FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id WHERE T1.title = 'African Egg'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

In films with a length duration of 113 minutes, how many of the films are starred by Kirk Jovovich?

SELECT COUNT(T1.actor_id) FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.length = 113 AND T1.first_name = 'Kirk' AND T1.last_name = 'Jovovich'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

In the film with an inventory ID between 20 to 60, how many of the films have a G rating?

SELECT COUNT(T1.film_id) FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id WHERE T2.inventory_id BETWEEN 20 AND 60 AND T1.rating = 'G'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Among films with a rental rate of 4.99, what is the total number of films starred by Bob Fawcett?

SELECT COUNT(T1.actor_id) FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.rental_rate = 4.99 AND T1.first_name = 'Bob' AND T1.last_name = 'Fawcett'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What is the inventory ID of the films starred by Russell Close with a duration between 110 to 150 minutes?

SELECT T4.inventory_id FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id INNER JOIN inventory AS T4 ON T3.film_id = T4.film_id WHERE T3.length BETWEEN 110 AND 150 AND T1.first_name = 'Russell' AND T1.last_name = 'Close'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What is the store and inventory ID of the film with the longest duration?

SELECT T2.store_id, T2.inventory_id FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id ORDER BY T1.length DESC LIMIT 1

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

List the titles of the films starred by Elvis Marx.

SELECT T3.title FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.length BETWEEN 110 AND 150 AND T1.first_name = 'Russell' AND T1.last_name = 'Close'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

In films with rental rate of 4.99, list down the inventory ID of the films starred by Lucille Dee.

SELECT T4.inventory_id FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id INNER JOIN inventory AS T4 ON T3.film_id = T4.film_id WHERE T1.first_name = 'Lucille' AND T1.last_name = 'Dee' AND T3.rental_rate = 4.99

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

List the store ID of the films with a rental rate greater than the 60% of average rental rate of all listed films.

SELECT T2.store_id FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id WHERE T1.rental_rate > ( SELECT AVG(T1.rental_rate) * 0.6 FROM film AS T1 )

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Among the films starred by Nick Wahlberg, what is the percentage of the films with G rating?

SELECT CAST(SUM(IIF(T3.rating = 'G', 1, 0)) AS REAL) / COUNT(T3.film_id) FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'Elvis' AND T1.last_name = 'Marx'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

List the address in Texas in the ascending order of city id.

SELECT address FROM address WHERE district = 'Texas' AND city_id = ( SELECT MIN(city_id) FROM address WHERE district = 'Texas' )

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Find the full name and email address of inactive customers whose record was created in 2006.

SELECT first_name, last_name, email FROM customer WHERE STRFTIME('%Y',create_date) = '2006' AND active = 0

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What percentage of the movies are PG-13?

SELECT CAST(SUM(IIF(rating = 'PG-13', 1, 0)) AS REAL) * 100 / COUNT(film_id) FROM film

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Please list the top ten movies with the most price per day in descending order of price per day.

SELECT title FROM film ORDER BY rental_rate / rental_duration DESC LIMIT 10

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Calculate the average rent amount paid by the customer with customer id 15.

SELECT AVG(amount) FROM payment WHERE customer_id = 15

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

How many customers rented for an above-average period?

SELECT COUNT(customer_id) FROM rental WHERE return_date - rental_date > ( SELECT AVG(return_date - rental_date) FROM rental )

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Among the movies, what percentage are horror?

SELECT CAST(SUM(IIF(T2.name = 'horror', 1, 0)) AS REAL) * 100 / COUNT(T2.category_id) FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Give the full name of the actor who acted in the most number of movies?

SELECT T.first_name, T.last_name FROM ( SELECT T2.first_name, T2.last_name, COUNT(T1.film_id) AS num FROM film_actor AS T1 INNER JOIN actor AS T2 ON T1.actor_id = T2.actor_id GROUP BY T2.first_name, T2.last_name ) AS T ORDER BY T.num DESC LIMIT 1

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Give the full name of the actor who acted the most in drama movies?

SELECT T.first_name, T.last_name FROM ( SELECT T1.first_name, T1.last_name, COUNT(T2.film_id) AS num FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film_category AS T3 ON T2.film_id = T3.film_id WHERE T3.category_id = 7 GROUP BY T1.first_name, T1.last_name ) AS T ORDER BY T.num DESC LIMIT 1

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What is the difference in the average number of films rented each day in Australia and Canada?

SELECT AVG(IIF(T4.country = 'Australia', 1, 0)) - AVG(IIF(T4.country = 'Canada', 1, 0)) AS diff FROM customer AS T1 INNER JOIN address AS T2 ON T1.address_id = T2.address_id INNER JOIN city AS T3 ON T2.city_id = T3.city_id INNER JOIN country AS T4 ON T3.country_id = T4.country_id

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Of the movies in which Reese Kilmer acted, what percentage are action movies?

SELECT CAST(SUM(IIF(T4.name = 'Action', 1, 0)) AS REAL) * 100 / COUNT(T1.actor_id) FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film_category AS T3 ON T2.film_id = T3.film_id INNER JOIN category AS T4 ON T3.category_id = T4.category_id WHERE T1.first_name = 'Reese' AND T1.last_name = 'Kilmer'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Give the total amount of rent for the movie Clockwork Paradice.

SELECT SUM(T1.amount) FROM payment AS T1 INNER JOIN rental AS T2 ON T1.rental_id = T2.rental_id INNER JOIN inventory AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN film AS T4 ON T3.film_id = T4.film_id WHERE T4.title = 'CLOCKWORK PARADICE'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Find and list the full name of customers who rented more than five types of movies.

SELECT T.first_name, T.last_name FROM ( SELECT T1.first_name, T1.last_name, COUNT(T1.customer_id) AS num FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id INNER JOIN inventory AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN film AS T4 ON T3.film_id = T4.film_id INNER JOIN film_category AS T5 ON T4.film_id = T5.film_id GROUP BY T1.first_name, T1.last_name ) AS T WHERE T.num > 5

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What is the average number of actors acted in comedy movies?

SELECT AVG(T1.actor_id) FROM film_actor AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id INNER JOIN actor AS T4 ON T4.actor_id = T1.actor_id WHERE T3.name = 'comedy'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

In children's movies, which was rented the most?

SELECT T.title FROM ( SELECT T4.title, COUNT(T4.title) AS num FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id INNER JOIN inventory AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN film AS T4 ON T3.film_id = T4.film_id INNER JOIN film_category AS T5 ON T4.film_id = T5.film_id INNER JOIN category AS T6 ON T5.category_id = T6.category_id WHERE T6.name = 'Children' GROUP BY T4.title ) AS T ORDER BY T.num DESC LIMIT 1

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Calculate the percentage of customers who paid more than the average rent amount in store 1.

SELECT CAST(( SELECT COUNT(T1.customer_id) FROM customer AS T1 INNER JOIN payment AS T2 ON T1.customer_id = T2.customer_id WHERE T2.amount > ( SELECT AVG(amount) FROM payment ) ) AS REAL) * 100 / ( SELECT COUNT(customer_id) FROM customer )

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Find and list the full name of customers who rented more family movies than Sci-Fi movies.

SELECT DISTINCT IIF(SUM(IIF(T5.name = 'Family', 1, 0)) - SUM(IIF(T5.name = 'Sci-Fi', 1, 0)) > 0, T1.first_name, 0) FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id INNER JOIN inventory AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN film_category AS T4 ON T4.film_id = T3.film_id INNER JOIN category AS T5 ON T4.category_id = T5.category_id GROUP BY T1.customer_id

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Indicate the title of all the films rated as 'Adults Only'.

SELECT title FROM film WHERE rating = 'NC-17'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

How many actors with the surname Kilmer are there?

SELECT COUNT(actor_id) FROM actor WHERE last_name = 'Kilmer'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

How many movies have a length longer than 100?

SELECT COUNT(film_id) FROM film WHERE length > 100

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

How many payments were made throughout the month of August 2005?

SELECT SUM(amount) FROM payment WHERE payment_date LIKE '2005-08%'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

To which country does the address '1386 Nakhon Sawan Boulevard' belong?

SELECT T1.country FROM country AS T1 INNER JOIN city AS T2 ON T1.country_id = T2.country_id INNER JOIN address AS T3 ON T2.city_id = T3.city_id WHERE T3.address = '1386 Nakhon Sawan Boulevard'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What language was the most used in movies released in 2006?

SELECT T.language_id FROM ( SELECT T1.language_id, COUNT(T1.language_id) AS num FROM film AS T1 INNER JOIN language AS T2 ON T1.language_id = T2.language_id WHERE STRFTIME('%Y',T1.release_year) = '2006' GROUP BY T1.language_id ) AS T ORDER BY T.num DESC LIMIT 1

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Indicate the title of all the films that are in the Classics category.

SELECT T2.title FROM film_category AS T1 INNER JOIN film AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T1.category_id = T3.category_id WHERE T3.name = 'Classics'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

How many rentals did Ella Oliver hire in June 2016?

SELECT COUNT(T1.rental_id) FROM rental AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = 'ELLA' AND T2.last_name = 'ELLA' AND date(T1.rental_date) BETWEEN '2005-06-01' AND '2005-06-30'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

How many different clients have rented materials from Jon Stephens?

SELECT COUNT(T1.customer_id) FROM rental AS T1 INNER JOIN staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = 'Jon' AND T2.last_name = 'Stephens'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What is the total amount paid for rentals made on July 29, 2005?

SELECT SUM(T2.amount) FROM rental AS T1 INNER JOIN payment AS T2 ON T1.rental_id = T2.rental_id WHERE date(T1.rental_date) = '2005-07-29%'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What is the first name of the customers whose address is in the postal code that begins with 76?

SELECT T1.first_name FROM customer AS T1 INNER JOIN address AS T2 ON T1.address_id = T2.address_id WHERE SUBSTR(T2.postal_code, 1, 2) = '76'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

On what date was the rented material for the movie BLOOD ARGONAUTS returned?

SELECT T1.rental_date FROM rental AS T1 INNER JOIN inventory AS T2 ON T1.inventory_id = T2.inventory_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.title = 'BLOOD ARGONAUTS'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What is the title of the films in which Cuba Allen acted?

SELECT T3.title FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'Cuba' AND T1.last_name = 'Allen'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

How many actors acted in movies in the Music category?

SELECT COUNT(T1.actor_id) FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id INNER JOIN film_category AS T4 ON T3.film_id = T4.film_id INNER JOIN category AS T5 ON T4.category_id = T5.category_id WHERE T5.name = 'Music'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What is the full name of the actor who has acted the most times in comedy films?

SELECT T.first_name, T.last_name FROM ( SELECT T4.first_name, T4.last_name, COUNT(T2.actor_id) AS num FROM film_category AS T1 INNER JOIN film_actor AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T1.category_id = T3.category_id INNER JOIN actor AS T4 ON T2.actor_id = T4.actor_id WHERE T3.name = 'Comedy' GROUP BY T4.first_name, T4.last_name ) AS T ORDER BY T.num DESC LIMIT 1

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

How many customers did not rent material at Mike's store?

SELECT COUNT(T1.customer_id) FROM customer AS T1 INNER JOIN store AS T2 ON T1.store_id = T2.store_id INNER JOIN staff AS T3 ON T2.manager_staff_id = T3.staff_id WHERE T3.first_name != 'Mike'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Indicate the name of the actors of the films rated as 'Parents Strongly Precautioned' with the highest replacement cost.

SELECT T1.first_name, T1.last_name FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.rating = 'PG-13' ORDER BY T3.replacement_cost DESC LIMIT 1

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What is the name of the client who has the largest quantity of rented material without returning it?

SELECT T.first_name FROM ( SELECT T2.first_name, COUNT(T1.rental_date) AS num FROM rental AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id GROUP BY T2.first_name ) AS T ORDER BY T.num DESC LIMIT 1

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

How many customers live in the city of Miyakonojo?

SELECT COUNT(T3.customer_id) FROM city AS T1 INNER JOIN address AS T2 ON T1.city_id = T2.city_id INNER JOIN customer AS T3 ON T2.address_id = T3.address_id WHERE T1.city = 'Miyakonojo'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

How many non-active clients have not returned the rented material?

SELECT COUNT(T2.customer_id) FROM rental AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id WHERE T2.active = 0

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What is the title of the animated films that have the shortest length?

SELECT T1.title FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id ORDER BY T1.length LIMIT 1

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

In which country is the store where Hector Poinexter rents equipment located?

SELECT T5.country FROM customer AS T1 INNER JOIN store AS T2 ON T1.store_id = T2.store_id INNER JOIN address AS T3 ON T2.address_id = T3.address_id INNER JOIN city AS T4 ON T3.city_id = T4.city_id INNER JOIN country AS T5 ON T4.country_id = T5.country_id WHERE T1.first_name = 'HECTOR' AND T1.last_name = 'POINDEXTER'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What is the average rental payment in Horror movies?

SELECT AVG(T5.amount) FROM category AS T1 INNER JOIN film_category AS T2 ON T1.category_id = T2.category_id INNER JOIN inventory AS T3 ON T2.film_id = T3.film_id INNER JOIN rental AS T4 ON T3.inventory_id = T4.inventory_id INNER JOIN payment AS T5 ON T4.rental_id = T5.rental_id WHERE T1.name = 'Horror'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What is the average amount of rent that Christy Vargas paid?

SELECT AVG(T2.amount) FROM customer AS T1 INNER JOIN payment AS T2 ON T1.customer_id = T2.customer_id WHERE T1.first_name = 'CHRISTY' AND T1.Last_name = 'VARGAS'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What percentage of films with a length of less than 100 belong to the Drama category?

SELECT CAST(SUM(IIF(T2.length < 100 AND T3.name = 'Drama', 1, 0)) AS REAL) * 100 / COUNT(T1.film_id) FROM film_category AS T1 INNER JOIN film AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T1.category_id = T3.category_id

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What are the actors that have the same forename as Johnny? Please include in your answer the full names of these actors.

SELECT first_name, last_name FROM actor WHERE first_name = 'Johnny'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What are the address numbers that are located in Gansu district?

SELECT address_id FROM address WHERE district = 'Gansu'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Please list three types of film along with their IDs and the latest update.

SELECT DISTINCT name, category_id, last_update FROM category LIMIT 3

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Please list the full names of any three inactive customers.

SELECT first_name, last_name FROM customer WHERE active = 0 LIMIT 3

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What is the rental price per day for Airplane Sierra?

SELECT rental_rate / rental_duration AS result FROM film WHERE title = 'AIRPLANE SIERRA'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Where is store number 2 located?

SELECT T1.address, T1.address2, T1.district FROM address AS T1 INNER JOIN store AS T2 ON T1.address_id = T2.address_id WHERE T2.store_id = 2

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Which city does the address 1623 Kingstown Drive belong to?

SELECT T1.city FROM city AS T1 INNER JOIN address AS T2 ON T2.city_id = T1.city_id WHERE T2.address = '1623 Kingstown Drive'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Please name three cities that belong to Algeria.

SELECT T2.city FROM country AS T1 INNER JOIN city AS T2 ON T1.country_id = T2.country_id WHERE T1.country = 'Algeria'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What is the category of the film Agent Truman?

SELECT T3.name FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T1.title = 'AGENT TRUMAN'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Please list the titles of any three action films.

SELECT T1.title FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T3.name = 'Action' LIMIT 3

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What is the difference between the number of children's films and action films?

SELECT SUM(IIF(T2.name = 'Children', 1, 0)) - SUM(IIF(T2.name = 'Action', 1, 0)) AS diff FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Which district does Maria Miller live in?

SELECT T2.district FROM customer AS T1 INNER JOIN address AS T2 ON T1.address_id = T2.address_id WHERE T1.first_name = 'Maria' AND T1.last_name = 'Miller'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Who is the customer that is active and lives at 1795 Santiago de Compostela Way, Texas?

SELECT T1.first_name, T1.last_name FROM customer AS T1 INNER JOIN address AS T2 ON T1.address_id = T2.address_id WHERE T2.address = '1795 Santiago de Compostela Way' AND T1.active = 1

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

How many English films have a duration of over 50 minutes and the cost of replacement are under 10.99?

SELECT COUNT(T1.film_id) FROM film AS T1 INNER JOIN language AS T2 ON T1.language_id = T2.language_id WHERE T2.name = 'English' AND T1.length > 50 AND T1.replacement_cost < 10.99

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Who are the actors that act in the ACADEMY DINOSAUR film?

SELECT T1.first_name, T1.last_name FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.title = 'ACADEMY DINOSAUR'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Please list any two films that Penelope Guiness acted in.

SELECT T3.title FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'Penelope' AND T1.last_name = 'Guiness' LIMIT 2

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What is the percentage of documentary films?

SELECT CAST(SUM(IIF(T2.name = 'Documentary', 1, 0)) AS REAL) * 100 / COUNT(T1.film_id) FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

How many films in English are for adults only?

SELECT COUNT(T1.film_id) FROM film AS T1 INNER JOIN language AS T2 ON T1.language_id = T2.language_id WHERE T2.name = 'English' AND T1.rating = 'NC-17'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Which film has the longest duration?

SELECT title FROM film WHERE length = ( SELECT MAX(length) FROM film )

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

How many of the actors are named "Dan"?

SELECT COUNT(actor_id) FROM actor WHERE first_name = 'Dan'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What is the most common first name among the customers?

SELECT first_name FROM customer GROUP BY first_name ORDER BY COUNT(first_name) DESC LIMIT 1

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What are the ratings of the film featuring behind the scenes?

SELECT rating FROM film WHERE special_features LIKE '%Behind the Scenes%'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What is the largest number of films rented per customer?

SELECT COUNT(rental_id) FROM rental GROUP BY customer_id ORDER BY COUNT(rental_id) DESC LIMIT 1

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

List all the films with the word "Lacklusture" in their description.

SELECT title FROM film_text WHERE description LIKE '%Lacklusture%'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

How many films did a customer named Francis Sikes rent?

SELECT COUNT(T1.customer_id) FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id WHERE T1.first_name = 'FRANCIS' AND T1.last_name = 'SIKES'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Who is the manager of the store with the largest collection of films?

SELECT T.first_name, T.last_name FROM ( SELECT T3.first_name, T3.last_name, COUNT(T1.film_id) AS num FROM inventory AS T1 INNER JOIN store AS T2 ON T1.store_id = T2.store_id INNER JOIN staff AS T3 ON T2.manager_staff_id = T3.staff_id GROUP BY T3.first_name, T3.last_name ) AS T ORDER BY T.num DESC LIMIT 1

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What are the addresses of the inactive customers?

SELECT T2.address FROM customer AS T1 INNER JOIN address AS T2 ON T1.address_id = T2.address_id WHERE T1.active = 0

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Which category is the most common?

SELECT T.name FROM ( SELECT T2.name, COUNT(T2.name) AS num FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id GROUP BY T2.name ) AS T ORDER BY T.num DESC LIMIT 1

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Provide the cast for the film "Jason trap".

SELECT T1.first_name, T1.last_name FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.title = 'JASON TRAP'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Who is the customer with the largest payment for rental films?

SELECT T.first_name, T.last_name FROM ( SELECT T1.first_name, T1.last_name, SUM(T2.amount) AS num FROM customer AS T1 INNER JOIN payment AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.first_name, T1.last_name ) AS T ORDER BY T.num DESC LIMIT 1

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

List the top 5 most-rented films.

SELECT T.title FROM ( SELECT T3.title, COUNT(T2.inventory_id) AS num FROM rental AS T1 INNER JOIN inventory AS T2 ON T1.inventory_id = T2.inventory_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id GROUP BY T3.title ) AS T ORDER BY T.num DESC LIMIT 5

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Which country does Sasebo belong to?

SELECT T1.country FROM country AS T1 INNER JOIN city AS T2 ON T1.country_id = T2.country_id WHERE T2.city = 'Sasebo'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What are the addresses for the stores?

SELECT T2.address FROM store AS T1 INNER JOIN address AS T2 ON T1.address_id = T2.address_id

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

List all the animation titles.

SELECT T3.title AS per FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id INNER JOIN film AS T3 ON T1.film_id = T3.film_id WHERE T2.name = 'Animation'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What is the city with the most customers?

SELECT T.city FROM ( SELECT T1.city, COUNT(T3.customer_id) AS num FROM city AS T1 INNER JOIN address AS T2 ON T2.city_id = T1.city_id INNER JOIN customer AS T3 ON T2.address_id = T3.address_id GROUP BY T1.city ) AS T ORDER BY T.num DESC LIMIT 1

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Which actor acted in the most films?

SELECT T.first_name, T.last_name FROM ( SELECT T2.first_name, T2.last_name, SUM(T1.film_id) AS num FROM film_actor AS T1 INNER JOIN actor AS T2 ON T1.actor_id = T2.actor_id GROUP BY T2.first_name, T2.last_name ) AS T ORDER BY T.num DESC LIMIT 1

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

What percentage of films are horror films?

SELECT CAST(SUM(IIF(T2.name = 'Horror', 1, 0)) AS REAL) * 100 / COUNT(T1.film_id) FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id INNER JOIN film AS T3 ON T1.film_id = T3.film_id

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Please indicate the full name of actor id 5.

SELECT first_name, last_name FROM actor WHERE actor_id = 5

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

How many id movies have category id 11?

SELECT COUNT(film_id) FROM film_category WHERE category_id = 11

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Which category does BABY HALL film belong to?

SELECT T3.`name` FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T3.category_id = T2.category_id WHERE T1.title = 'BABY HALL'

bird

CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)

Give the full name of the actor with the highest rental rate.

SELECT T1.first_name, T1.last_name FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T3.film_id = T2.film_id ORDER BY T3.rental_rate DESC LIMIT 1

bird